25=3.41x^2

Solution for 25=3.41x^2 equation:

25=3.41x^2

We move all terms to the left:

25-(3.41x^2)=0

We get rid of parentheses

-3.41x^2+25=0

a = -3.41; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-3.41)·25
Δ = 341
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{341}}{2*-3.41}=\frac{0-\sqrt{341}}{-6.82}
=-\frac{\sqrt{}}{-6.82}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{341}}{2*-3.41}=\frac{0+\sqrt{341}}{-6.82}
=\frac{\sqrt{}}{-6.82}
$